In an ap first term is 12 and the d is 6 if kast term is 253 ,find. Its middle term
Answers
Answered by
0
Answer:
The middle term of the sequence is 132.
Step-by-step explanation:
In an A.P., first term = a = 12, common difference = d = 6 and last term = tn = 253
∵ tn = a + (n-1) d
∴ 253 = 12 + (n-1) 6
253 = 12 + 6n - 6
253 = 6 + 6n
253 - 6 = 6n
247 = 6n
247 / 6 = n
n = 41
Total number of terms is 41.
Hence, the middle term of the sequence will be 21st term i.e. t21
∴ t21 = a + (n-1) d
t21 = 12 + (21-1) 6
t21 = 12 + (20)6
t21 = 12 + 120
t21 = 132
Answered by
0
Answer:
The last term of this AP cannot be 253
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