Math, asked by Hyperspy, 8 months ago

In an AP

Given a = 2 ; d = 8 ; Sn = 90

Find n and an.​

Answers

Answered by Anonymous
34

Given :-

  • a = 2
  • d = 8
  • Sn = 90

To Find :-

  • n and an.

Solution :-

Sn = n/2 [2a + (n - 1)d]

➜ 90 = n/2 [2 × 2 + (n - 1) × 8]

➜ 90 = n/2 [5 + 8n - 8]

➜ 90 = n/2 [8n - 4]

➜ 90 = 4n/2 [2n - 1]

➜ 90 = 2n [2n - 1]

➜ 4n² - 2n = 90

➜ 4n² - 2n - 90 = 0

➜ 2(2n² - n - 45) = 0

➜ 2n² - n - 45 = 0

➜ 2n² - 10n + 9n - 45 = 0

➜ 2n(n - 5) + 9(n - 5) = 0

➜ (n - 5) (2n + 9) = 0

➜ n = 5 (or) n = -9/2 (discarded)

➜ n = 5

an = a5

➦ a + 4d

➦ 2 + 4 × 8

➦ 2 + 32

➦ 34

Hence,

• n = 5

• an = 34

Answered by soumya235
3

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