Question

In an AP,given a=5,d=3,an=50find n and sn ​

Answer 1

Answer:

Answer is

Step-by-step explanation:

an=a+(n-1)d

50=5+3n-3

50=2+3n

50-2=3n

48=3n

n=48/3

n=16

Answer 2

$hope \: it \: helps \: you$

$tn = a + ( n- 1)d$

$50 = 5 + (n - 1)3$

$50 = 5 + 3n - 3$

$50 - 2 = 3n$

$48 = 3n$

$so \: \: \: \: n = 16$

$sn = n \div 2(2a + (n - 1)d)$

$s16 = 16 \div 2(2 \times 5) + 15 \times 3$

$s16 = 8 \times (10 + 45)$

$s16 = 8 \times 55$

$therefore \: \: \: \: s16 = 440$