in an ap
given a = 7, a 13 35 find a where d where a=1st term
do=common difference an=nth term.
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given a = 7, a 13 35 find a where d where a=1st term
do=common difference an=nth term.
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Answer:
First we need to find the common difference
a1=7
a13=35
So we know that nth term of AP is given by a1+(n-1)d
So 13th term is given by
a13=a1+12d=7+12d=35.
Now d=28/12.
Sum to n terms of AP is given by
Sn=n/2 * (2a1+(n-1)d)
S13=13/2 * (2*7+(13-1)(28/12))
=13/2* (14+28)
=13/2* (42)
=13*21
=273 which is the correct answer for sum upto 13th term of this AP:))
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