In an AP
given d=5, S9=75,
find a and a9
Answers
Answered by
2
Answer:
d=5,s
9
=75
s
9
=
2
9
[2a+(9−1)5]
75=
2
9
[2a+40]
150=9[2a+40]
150=18a+360
150−360=18a
−210=18a
18
−210
=a
a=
3
−35
a
9
=a+(9−1)5
a
9
=
3
−35
+40
a
9
=
3
−35+120
a
9
=
3
−85
Step-by-step explanation:
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