In an AP:
(i) given a = 5, d = 3, an = 50, find n and Sn.
(ii) given a = 7, a13
7, a13 = 35, find d and S13.
(iii) given a 12 = 37, d = 3, find a and S12.
(iv) given a3 = 15, S10 = 125, find d and alo.
(v) given d = 5, S9 = 75, find a and ag.
- On find nan an.
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hope it's helpfull dear friend
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Step-by-step explanation:
i) to find: n=?
an= a+(n-1)d
50 = 5+(n-1)3
50=5+3n-3
50=5-3+3n
50=2+3n
50-2=3n
48=3n
n=48/3
n=16
to find: Sn = S16= ?
Sn = n/2[2a + (n-1)d]
S16= 16/2 [2(5) + (16 - 1)3]
= 8[10 + 15 × 3]
= 8[10 + 45]
= 8 × 55
=440
S16 = 440
ii) ur question is not understandable
iii) to find: a = ?
an = a + (n-1)d
a12 = a + (12 - 1)3
37 = a + 11 × 3
37 = a + 33
37 - 33 = a
a = 4
to find : S12=?
Sn = n/2 [2a + (n - 1)d]
S12 = 12/2 [2(4) + (12 - 1)3]
= 6[8 + 11 × 3]
= 6[8 + 33]
= 6 × 41
= 246
S12 = 246
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