In an ap if 12th term is -13and the sum of 1st 4 terms is 24. What is the sum of the 1st 10 terms
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In an ap if 12th term is -13 and the sum of 1st 4 terms is 24. What is the sum of the 1st 10 terms
- Given t12 = - 13, S4 = 24.
- We know that tn = a + (n – 1)d
- -13 = a + (12 – 1)d
- So a + 11d = - 13
- We know that Sn = n/2 (2a + (n – 1)d)
- 24 = 4/2 (2a + (4 – 1) d)
- 24 = 2(2a + 3d)
- 2a + 3d = 12
- Now a + 11d = - 13
- 2a + 3d = 12
- Multiply eqn 1 by 2 we get
- 2a + 22d = - 26
- 2a + 3d = 12
- 19d = - 38
- So d = - 2
- Also 2a – 6 = 12
- 2a = 18
- So a = 9
- Now for sum of 10 terms we have a = 9, d = - 2 and n = 10
- Sn = n/2 (2a + (n – 1)d)
- = 10/2 (2(9) + (10 – 1) (-2)
- = 5(18 – 18)
- = 0
Therefore sum of 10 terms is zero
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