Question

In an ap, if a=3.5, d=0, n = 101, then find the value of an

Answer 1

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Answer 2

Given :

a=3.5, d=0, n = 101

To find :

find the value of an

Solution:

First term = a = 3.5

Common difference = d = 0

Number of terms = n = 101

We are supposed to find the value of $a_n$

Formula : $a_n=a+(n-1)d$

$a_{101}=3.5+(101-1)(0)$

$a_{101}=3.5$

Thus the value of $a_n$ = 3.5