In an AP if a = 3, a, = 103 and S, = 1113, then n is
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Let a=113
d=108−113=−5
Assuming the nth term to be 0
We know:
T
n
=a+(n−1)d
∴0=113+(n−1)(−5)
⇒(n−1)=
5
113
=22.6
⇒n=23.6
∴ 24th term will be the first negative term.
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