IN an AP if a =3 ,d=2,an=50 find the n and Sn
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1
Answer:
Given :- a = 3 , d = 2 , a = 50
To find :- n and Sn
Solution :- tn = a + ( n - 1 ) x d
= 3 + ( n - 1 ) x 2
= 3 + 2n - 2
= 1 + 2n
n = 1 /2
' n = 1/2 '
Sn = n / 2 [ 2a + ( n - 1 ) x d ]
Answered by
0
Answer:
here n is 24
and now we can find Sn by putting the formula
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