Question

in an ap if a=6 d=3 then the sum of first 10 sum is ​

Answer 1

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$\bold{ \underline{ \underline{given}}}$

a = 6

d = 3

n = 10

we know that..

$sn = \frac{n}{2} \times (2a + (n - 1)d) \\ sn = \frac{10}{2} \times (2 \times 6 + 9 \times 3) \\ sn = 5 \times (12 + 27) \\ sn = 5 \times 39 \\ sn = 195$

so sum of first 10 terms of an AP is 195

Answer 2

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so sum of first 10 terms of an AP is 195