in an AP ,if a=8 n=5 and Tn =0, then find the value of d
YASHIKAJINDAL:
Tn=0,a=8,n=5
Tn=a+(n-1)d
0=8+(5-1)d
-8=4d
d=-2
Answers
Answered by
13
a = 8
n = 5
Tn = 0
Tn = a + ( n - 1 )d
0 = 8 + 4d
- 8 = 4d
- 2 = d
n = 5
Tn = 0
Tn = a + ( n - 1 )d
0 = 8 + 4d
- 8 = 4d
- 2 = d
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Answered by
6
Heya,
According to the question,
In an A.P.
a = 8
n = 5
Tn = 0
So,
Tn = a + (n - 1)d
0 = 8 + (5 - 1)d
d = -8/4
d = -2. ..... Answer
Hope this helps....:)
According to the question,
In an A.P.
a = 8
n = 5
Tn = 0
So,
Tn = a + (n - 1)d
0 = 8 + (5 - 1)d
d = -8/4
d = -2. ..... Answer
Hope this helps....:)
hello
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