In an AP if a2 =13 a4 =3. find a1 and a3?
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Hope this may help uh dear!!!
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a2=a+d
13=a+d
13-d=a.....(i)
3=a+3d
and a=13-d
3=13-d+3d
3-13=2d
-10/2=d
-5=d
putting value of d in eq(i)
13-d=a
13-(-5)=a
13+5=a
18=a
a1=18
a3=a+2d
=18+2*-5
=18-10
=8
I hope it will help you!!!!!!
13=a+d
13-d=a.....(i)
3=a+3d
and a=13-d
3=13-d+3d
3-13=2d
-10/2=d
-5=d
putting value of d in eq(i)
13-d=a
13-(-5)=a
13+5=a
18=a
a1=18
a3=a+2d
=18+2*-5
=18-10
=8
I hope it will help you!!!!!!
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