in an AP ,if a2=7.3/4,a29=1,an=-6.1/2,then n=?
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Answer:
an=a+(n-1)d
Step-by-step explanation:
a2=a+(2-1)d
7.3/4=a+d. ....I
again
a29=a+(29-1)d
1=a+28d......ii
from I and ii
7.3/4=a+d
1=a+28d
changing sign
- - -
a and a cancel
7.3/4-1=d-28 d
0.825=-27d
d=0.825/27
d=0.03555
substituting value of d in I
7.3/4=a+0.03055
a=-1.7944
now an= a+(n-1)d
-6.1/2=1.7944+(n-1)0 .0355
*solve it *
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