In an AP, if an = 2n - 3 find a3
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If Tn=2n+3 then,
T1=(2×1)+3=2+3=5
T2=(2×2)+3=4+3=7
T3=(2×3)+3=6+3=9
Therefore, S3 is the sum of T1, T2 and T3 that is:
S3=T1+T2+T3=5+7+9=21
Hence, a3=21.
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