in an AP if an=4n-3 find it's first 4th terms
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Answer:
t
n
=4n−3
Put n = 1
∴t
1
=4×1−3
=4−3=1
∴ First term (t
1
)=1
Put n = 2
∴t
2
=4×2−3
=8−3=5
so, 4th term is : a+3d
1+3(4)
=13
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