In an ap if an+5=35 and an+1 =23 then the common difference is
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Tn+5=35
a+(n+5-1)d=35
a+nd+4d=35
Tn+1=23
a+(n+1-1)d=23
a+nd=23
substrate eq 1 and 2
a+nd+4d-a-nd=35-23
4d=12
d=3
Step-by-step explanation:
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