Question

In an AP if d=3 then a5-a7=----

Answer 1

Step-by-step explanation:

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Answer 2

$Given \: in \: an \:A.P , \\common \: difference (d) = 3$

$We \: know \: that ,$

$a_{6} - a_{5} = d = 3 \: --(1)$

$and \: a_{7} - a_{6} = d = 3 \: --(2)$

/* Add Equations (1) and (2) , we get */

$\cancel {a_{6}} - a_{5} + a_{7} - \cancel {a_{6}} = 3 + 3$

$\implies - a_{5} + a_{7} = 6$

/* Multiplying bothsides by (-1), we get */

$\implies -1( - a_{5} + a_{7} )= - 6$

$\implies a_{5} - a_{7} = - 6$

Therefore.,

$\red { in \: an \:A.P , d= 3} \\\green { \:then \: a_{5} - a_{7} = - 6}$

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