Question

In an AP if S10=35 and S9=28 then the value of a10

Answer 1

Your Answer is 65⅓ = 65.33

Step-by-step explanation:

a1 = first term, a10 = 10th term

S10 = ½( 2a1+9d)

S9 = ½(2a1+8d)

2S10 - 2S9 = d

d= 35-28 =7

according to the question

35×2= 2a1+(9×7)

=> a1= ½[70-63] =(7/2)

now, a10= a1+9d = (7/2)+(9×7)

=65⅓. (ans)

hope you will understand...