Question

In an Ap if s20=32 and s19= 28 then the value of a20 is​

Answer 1

Step-by-step explanation:

An = a+( n-1) d

A20 = a +(20-1)d ---(1)

s20 = 32

-s19 = - 28

d = 4

from (1)

a20 = a + 28×4

= a+ 112

Answer 2

The value of $a_{20}$ is 4.

Step-by-step explanation:

According to the given information, we are given that, sum of first 20 terms of the arithmetic series is 32 and the sum of the first 19 terms of the arithmetic series is 28. We have to find the value of the 20th term of the arithmetic series.

We know that in an arithmetic sequence, when a is the first element of the arithmetic series, $a_{n}$ is the last term of the arithmetic series, d is the common difference present between the terms of the series and n is the place value of a particular element and n  represents the nth term of the arithmetic sequence, the formula is $a_{n}$ = a + (n-1)d.

Also, since the sum of the first 20 terms and the sum of the first 19 terms is given, subtracting the sum of the first 19 terms from the sum of the first 20 terms will give the value of the 20th term of the arithmetic series. Thus, the value of the arithmetic series is

$s_{20} - s_{19} \\= 32 - 28\\= 4$

Thus, the value of $a_{20}$ is 4.

Learn more here

https://brainly.in/question/5967704

Learn more

https://brainly.in/question/4935086