In an AP, if s5+s7= 167 and s10= 235, then find the AP, where Sn denotes the sum of
its first n terms.
Ayus2001:
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the series is 1,6,11,16,........
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Answer:
S5+S7=5/2(2a+4d) +7/2(2a+6d)=167
=5a+10d+7a+21d=167
=12a+31d=167 [let this be eqn 1]
similarly,
from S10=235, we get 2a+9d=47 {let this be equation 2}
by solving eqn 1 and 2, we get a=1 and d=5
therefore the ap is 1,6,11........
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