in an ap if sum of 5th and 25th term is 106 then the 15tg term is
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Let a be the first term of AP and aₙ be the nth term of AP
a₅=a+4d
a₂₅=a+24d
a₅+a₂₅=106
2a+28d=106
a+14d=53
And a₁₅=a+14d
So
the 15th term of AP is 53
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Answer:
53
Step-by-step explanation:
nth term=An=a+(n-1)d
5th term = A5=a+(5-1)d=a+4d
25th term=A25=a+(25-1)d=a+24d
5th term+25th term=106
a+4d+a+24d=106
2a+28d=106
2(a+14d)=106
a+14d=53
15th term=A15=a+(15-1)d=a+14d=53
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