Question

In an ap, if the ratio of 4th and 8th term is 7:13 and 6th term is 4 more than twice the second term. find the ap.

Answer 1

Answer:

5,8,11,14,17,...

Step-by-step explanation:

t(n)=a+(n-1)d

$\frac{a+3d}{a+7d}$=======$\frac{7}{13}$

13a+39d=7a+49d

6a=10d======= a=$\frac{5d}{3}$------------ (eqn1)

#a+5d=4+2(a+d)

a-3d+4=0=====$\frac{5d}{3}-3d+4=0$

====d=3 ===a=5

Therefore the required A.P is 5,8,11,14,17,.

Step-by-step explanation: