In an AP if the sum of 8 terms is 536 and last term is 134 find the AP.
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Given : the sum of 8 terms is 536 and last term is 134
To Find : AP
Solution:
Sum of AP = (n/2) ( first Term + last term)
=> 536 = (8/2) ( first Term + 134)
=> 134 = first Term + 134
=> first Term = 0
a = 0
8th term = a + 7d
= 0 + 7d = 134
=> d = 134/7
AP is
0 134/7 , 2 * 134/7 , 3 * 134 /7 ___________, 6 * 134/7 , 134
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