Question

In an AP if the sum of 8 terms is 536 and last term is 134 find the AP.

Answer 1

Given :   the sum of 8 terms is 536 and last term is 134

To Find : AP

Solution:

Sum of AP  = (n/2) ( first Term + last term)

=> 536 = (8/2) (  first Term  + 134)

=> 134 = first Term  + 134

=>  first Term  = 0

a = 0

8th term  = a + 7d

= 0 + 7d  = 134

=> d = 134/7

AP is

0    134/7  ,  2 * 134/7  , 3 * 134 /7  ___________, 6 * 134/7 ,    134

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