Question

in an AP is 3,7,,11,15,.........find the next four term​

Answer 1

Answer:

19,23,27,31

d=7-3=4

a5=a4+d

=15+4=19

a6=a5+d

=19+4=23

a7=a6+d

=23+4=27

a8=a7+d

=27+4=31

Answer 2

$a1 = a = 3 \\ d = a2 - a1 \\ d = 7 - 3 \\ d = 4$

$a5 = a + 4d \\ a5 = 3 + 4(4) \\ a5 = 3 + 16 \\ a5 = 19$

$a6 = a + 5d \\ a6 = 3 + 5(4) \\ a6 = 3 + 20 \\ a6 = 23$

$a7 = a + 6d \\ a7 = 3 + 6(4) \\ a7 = 3 + 24 \\ a7 = 27$

$a8 = a + 7d\\ a8 = 3 + 7(4) \\ a8 = 3 + 28\\ a8 = 31$

So, the next four terms are 19 , 23 , 27 , 31