Question

in an ap is s6+s7 = 167 S10=235 then find the ap is sn denotes the sum of its first n terms​

Answer 1

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[2a+6d]=167

⇒10a+20d+14a+42d=334

⇒24a+62d=334      

Given: S$_{10}$   =235

So 5(2a+9d)=235

⇒2a+9d=47      

 

24a+108d=564

Subtracting equation

−46d=−230

∴d=5

Substring the value of d=5 in equation (1) we get

2a+9(5)=47 or 2a=2

∴a=1

Then A.P is 1,6,11,16,21,⋯