In an AP. it is given that common difference is 5 and sum of its first ten terms is 75. find term of the AP
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Answered by
2
Answer:
-15
Step-by-step explanation:
sum of n terms =n/2[2a+(n-1)d] =75
= 10/2[2a+(n-1)d]=75
=5[2a+9(5)]=75
=2a+45=75/5
=2a=15-45
=a=-30/2
a= -15
Answered by
4
Answer:
AP=15,20,25,30.......
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