In an AP, it is given that S5+ S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms.
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Answer:
1, 6, 11, 16..........
Step-by-step explanation:
S5 + S7 = 167
Sn = n/2 (2a + (n-1)d)
substitute d = 5 in equ 1
substitute d = 5 in equ 2
2a + 9d = 47
2a + 9(5)= 47
2a + 45 = 47
2a = 47 - 45
2a = 2
a = 2/2
a = 1
the AP is
1, 6, 11, 16 ..........
hope you get your answer
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