IN AN AP OF FIRST n TERMS IS 3n 2 /2+13n/2. FIND ITS 25th TERM
abhi178:
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25 th term
= 3(25)^2/2 +13(25)/2
=3x625/2 + 325/2
=1100
= 3(25)^2/2 +13(25)/2
=3x625/2 + 325/2
=1100
Answered by
1
1100
3x25x25/2=1875/2
13x25/2= 325/2
so, 1875/2+ 325/2=1100
3x25x25/2=1875/2
13x25/2= 325/2
so, 1875/2+ 325/2=1100
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