in an AP of n terms ,if the last term is negative of first term ,then the sum of n terms of the AP is
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we know that sum of n terms is Sn=n/2[a+l]
where l = last term
a=first term
given,
the last term is negative of first term
so let as assume first term=x
last term =-x
Sn =n/2[x-x]
Sn=0
I HOPE THIS WILL HELP U FRND
where l = last term
a=first term
given,
the last term is negative of first term
so let as assume first term=x
last term =-x
Sn =n/2[x-x]
Sn=0
I HOPE THIS WILL HELP U FRND
Answered by
3
Define x:
Let the first term be x
The last term is negative of first term
⇒ The last term is -x
Sum of AP:
Formula: Sum = n/2 ( a1 + an)
Sub in a1 = x and an = -x:
Sum = n/2 ( x - x)
Sum = n/2 (0)
Sum = 0
Answer: The sum of the AP is zero
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