In an AP of natural numbers S20 +S15=..........................?
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A.P:1,2,34........20
a=1,d=2-1=1,n=20
S20=n/2(2a+(n-1)d)
=20/2(2(1)+(20-1)(1)
=10(2+19)
=10(21)
=210
a=1,d=2-1=1,n=15
S15=n/2(2a+(n-1)d)
=15/2(2(1)+(15-1)(1)
=15/2(2+14)
=15/2(16)
=15(8)
=120
S20+S15=210+120
=330
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