In an ap of three terms sum of the terms is 60 and sum of squares of extreme is 850 find the terms
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Let three terms of AP be α-β , α , α+β
ATQ
α-β+α+α+β=60
3α=60
α=20
Again ATQ
(α-β)²+(α+β)²=850
α²+β²-2αβ+α²+β²+2αβ=850
2α²+2β²=850
2(α²+β²)=850
α²+β²=425
20²+β²=425
400+β²=425
β²=25
β=5
∴terms of AP=15 , 20 , 25
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