in an ap s10-s9 is equal to
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Answer:
Step-by-step explanation:
s10= n/2(2a+(n-1)d)
s9=n/2(2a+(n-1)
s10=5(2a+9d)
s9=9/2(2a+8d)
s10=10a+45d
s9=9a+36d
we have to find s10-s9
=10a+45d -(9a+36d)
=a + 9d ( this is T10)
is the answer
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