in an AP second term is 8, fifth term is 17. Find 19th term
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Answered by
1
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Good evening
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Given that
=> T2 = 8
=> a + d = 8
=> a = 8 - d...........( i )
And
=> T5 = 17
=> a + 4d = 17
From ( i ) eq.
=> 8 - d + 4d = 17
=> 3d = 17 - 8
=> d = 9/ 3
=> d = 3
So we have,
=> a = 8 - d
=> a = 8 - 3
=> a = 5
And d = 3
So the t 19 nineteenth term = a + 18d
=> 5 + 18 x 3
=> 5 + 54
=> 59
So the nineteenth term is 59.
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Good evening
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Given that
=> T2 = 8
=> a + d = 8
=> a = 8 - d...........( i )
And
=> T5 = 17
=> a + 4d = 17
From ( i ) eq.
=> 8 - d + 4d = 17
=> 3d = 17 - 8
=> d = 9/ 3
=> d = 3
So we have,
=> a = 8 - d
=> a = 8 - 3
=> a = 5
And d = 3
So the t 19 nineteenth term = a + 18d
=> 5 + 18 x 3
=> 5 + 54
=> 59
So the nineteenth term is 59.
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Answered by
3
a+d=8 -(1)
a+4d=17 -(2)
subtract equation 1 and 2
we will get d=3
a+d=8
a+3=8
a=5
an=a+(n-1)d
a19=5+(19-1)3
=5+18×3
=5+54
=59
Hence the 19th term is 59.
a+4d=17 -(2)
subtract equation 1 and 2
we will get d=3
a+d=8
a+3=8
a=5
an=a+(n-1)d
a19=5+(19-1)3
=5+18×3
=5+54
=59
Hence the 19th term is 59.
Anonymous:
Nice ans......
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