Question

In an AP Sn = 3n+5 then the value of 'd' is​

Answer 1

Answer: -5

Step-by-step explanation:

sn=3n+5

s1=a1=3(1)+5=8

s2=a1+a2=3(2)+5=6+5=11

   =a1+a2=11

   =a2=11-a1=11-8=3

comman difference,d=a2-a1

                                   =3-8= -5

Answer 2

Answer:

      d = -5

Step-by-step explanation:

Given :- In an AP, Sn=3n+5 then, the value of ‘d’ is:

Solution :-

→ Sn = 3n + 5

so,

at n = 1,

→ S1 = 3*1 + 5 = 3 + 5 = 8

at n = 2

→ S2 = 3*2 + 5 = 11

Let first term of given AP is a and common difference is d .

so,

→ S1 = a1 = 8

→ S2 = a1 + a2

→ S2 = a1 + (a1 + d)

then,

→ a1 + (a1 + d) = 11

→ 8 + 8 + d = 11

→ 16 + d = 11

→ d = 11 - 16

→ d = (-5) (Ans.)