Question

in an Ap sn=50 and sn-1=48 then the value of an is​

Answer 1

SOLUTION

GIVEN

In a AP $\sf{s_n = 50 \: \: and \: \: \: s_{n-1} = 48}$

TO DETERMINE

The value of $\sf{a_n }$

EVALUATION

Here it is given that in an Arithmetic progression

$\sf{s_n = 50 }$

⇒ Sum of first n terms = 50

$\sf{s_{n - 1} = 48 }$

⇒ Sum of first (n - 1 ) terms = 48

Thus we get

$\sf{a_n}$

= The n th term of the AP

= Sum of first n terms - Sum of first (n - 1 ) terms

= 50 - 48

= 2

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