Question

in an AP sum of 4th and 8th term is 22 and product of 2nd and 6th term is 33 find the AP​

Answer 1

Step-by-step explanation:

Here,

A4 + A8 = 22

A+3D + A+ 7D = 22

2A +10D = 22

A + 5D = 11

A = 11 – 5D .....(1)

Now,

A2 × A6 = 33

A+ 1D × A+ 5D = 33

11 – 5D + 1D × 11 – 5D + 5D = 33. ( FROM 1 )

11 – 4D × 11 = 33

11 – 4D = 33

4D = – 22

D = – 11/2

So, A = 11 – 5× –11/2

A= 11 + 55/2

A= 77/2

Hence, Required AP = 77/2 , 33 , 55/2 ,..