in an AP sum of an n term is 2n^2+3n find common difference
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Let here "n" suffix be "x"
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Given: Sₓ = 2x² + 3x
aₓ = Sₓ - Sₓ₋₁
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Sₓ-₁ = 2(x-1)² + 3(x-1)
= 2(x²-2x+1) + 3(x-1)
= 2x² - 4x + 2 + 3x - 3
= 2x² - x - 1
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Then, aₓ = 2x² + 3x - 2x² + x + 1
= 4x + 1
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As aₓ = 4x + 1
Then, a₁ = 4(1) + 1
a = 4 + 1 = 5
a₂ = 4(2) + 1
= 8 + 1 = 9
Then d = a₂ - a₁
d = 9 - 5 = 4
Hence common difference (d) is 4
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☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
______________________________________________________
Given: Sₓ = 2x² + 3x
aₓ = Sₓ - Sₓ₋₁
______________________________________________________
Sₓ-₁ = 2(x-1)² + 3(x-1)
= 2(x²-2x+1) + 3(x-1)
= 2x² - 4x + 2 + 3x - 3
= 2x² - x - 1
_______________________________________________________
Then, aₓ = 2x² + 3x - 2x² + x + 1
= 4x + 1
________________________________________________________
As aₓ = 4x + 1
Then, a₁ = 4(1) + 1
a = 4 + 1 = 5
a₂ = 4(2) + 1
= 8 + 1 = 9
Then d = a₂ - a₁
d = 9 - 5 = 4
Hence common difference (d) is 4
______________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
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