Question

in an ap sum of first four trems 26 and first and 4th terms square sum of 125 find 4 trems of ap​

Answer 1

Answer:

26

Step-by-step explanation:

a1+(a1+d)+(a1+2d)+(a1+3d)=26

2(2a1+3d)=26

2a1+3d=26

2a1+3d=13.•••••••••(1)

first and temis 125

1. a1/2+a1/2+6a+d+gd/2=125
2. 2a1/2+6a1d+gd2=125

[2]:a1=13-3 d

2[13-3d]2+6d×(13-3_2+9d2=125

2[(169-7_4_8d+9d2)]+39d-9d/2+9d2=125

169-78d+9d2+9d2=125.

1. 169-78d+9d2+78d=250
2. 9d2=81
3. D2=9
4. d=3
5. 2a1=3d=13
6. 2a1=9=13
7. a1=4
8. a1=2

A2=2+3=5

A3=5+3=8

1. a4=8+3=11