in an ap sum of first three terms is 21 product is 231 find the three
terms of an ap
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4
a-d+a+a+d =21
3a=21
a=7
(a-d)(a)(a+d)=a(a^2-d^2)=231
7(49_d^2)=231
49-d^2=77
-d^2=28
Answered by
1
3,7,11 will be the terms
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