in an ap t1=22,tn= -11,sn= 66, find n
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this is ur required solution
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vishnu24choudhp196qk:
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Answer:
n=12
Step-by-step explanation:
a+(n-1)d=an
22+(n-1)d=-11
(n-1)d=-33
Sn=n/2(2a+(n-1)d)
66=n/2(2(22)+(n-1)d)
66×2=n(44-33)
132=n(11)
n=132/11
n=11
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