in an ap T7 is equals to 45 and t9 is equals to 59 find the AP
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T7 = 45
=> a + 6d = 45 ------(1)
T9 = 59
=> a + 8d = 59 ------(2)
On subtracting equation 1 from 2, we get
2d = 14
=> d = 7
Now,
On substituting the value d in equation 1, we get
a + 6(7) = 45
=> a + 42 = 45
=> a = 3
Required AP is :-
3, 10, 17,........
=> a + 6d = 45 ------(1)
T9 = 59
=> a + 8d = 59 ------(2)
On subtracting equation 1 from 2, we get
2d = 14
=> d = 7
Now,
On substituting the value d in equation 1, we get
a + 6(7) = 45
=> a + 42 = 45
=> a = 3
Required AP is :-
3, 10, 17,........
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