Question

in an AP the 10th term is 46, sum of the 5th and 7th term is 52 find the AP

Answer 1

a10=a+9d=46
a5+a7=a+4d+a+6d=52
2a+10d=52
a+5d=26
Now we have 2 equation
a+9d=46
a+5d=26
Solving
d=5
a=1
Thus AP is
1,6,11,16.....
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Answer 2

a(10)=46
a+9d=46. -(1)
a(5)+a(7)=52
a+4d+a+6d=52
2a+10d=52
a+5d=26. -(2)
subtract (1)from(2),
a+9d-a-5d=46-26
4d=20
d=5
a=1
AP:1,(1+5),(1+10),(1+15),..............
Ap:1,6,11,16,21,26,........... ........ ...........
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