in an AP the 4th term exceed the thrice the second term by 2 and 8th term less than the twice the 5th term by 4 find the AP
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Answer:
3, 4, 5, 6, 7, 8, 9, 10,....
Explanation:
T(4) = T(2) + 2 --> eqn.(1)
T(8) = 2(T5) - 4 --> eqn.(2)
Using: a + (n - 1) d ,
From eqn.1
a + 3d = ( a + d) + 2
a + 3d = a + d + 2
3d - d = 2
2d = 2
d = 1
From eqn.2
a + 7d = 2(a + 4d) - 4
a + 7 = 2(a + 4) - 4 as d=1
a + 7 = 2a + 8 - 4
a + 7 = 2a + 4
2a - a = 7 - 4
a = 3
Hence the AP will be:
3, 4, 5, 6, 7, 8, 9, 10, .....
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