Question

in an AP the 4th term exceed the thrice the second term by 2 and 8th term less than the twice the 5th term by 4 find the AP​

Answer 1

Answer:

3, 4, 5, 6, 7, 8, 9, 10,....

Explanation:

T(4) = T(2) + 2 --> eqn.(1)

T(8) = 2(T5) - 4 --> eqn.(2)

Using: a + (n - 1) d ,

From eqn.1

a + 3d = ( a + d) + 2

a + 3d = a + d + 2

3d - d = 2

2d = 2

d = 1

From eqn.2

a + 7d = 2(a + 4d) - 4

a + 7 = 2(a + 4) - 4 as d=1

a + 7 = 2a + 8 - 4

a + 7 = 2a + 4

2a - a = 7 - 4

a = 3

Hence the AP will be:

3, 4, 5, 6, 7, 8, 9, 10, .....