Question

in an AP ,the first term is 2 and the sum of the first five terms is one -fourthof the AP is 112

Answer 1

Given that a=2.
Sum of first five terms is 1/4 of 112
Which means the sum of first five terms is 28
by this Sn=n/2[a+(n-1)d]
here n=5
S5=5/2[2+(5-1)d]
S5=5/2[2+4d]
28=5(1+2d). {2 taken common and cancelled}
28=5+10d
28-5=10d
23=10d
»d=23/10
»d=2.3

.°.the AP is 2,4.3,6.6,8.9,11.2,.......so on




THATS IT BRO GOOD LUCK. :)