In an AP the first term is 2 , the last term is 29. Find the number terms of AP
whose sum is 155.
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Answer:
10 terms
Step-by-step explanation:
A=2
An=A+[n-1]d=29
2+[n-1]d=29
[n-1]d=27 [1]
Sn=155
Sn =n/2 [2A+[n-1]d=155
substitute eq [1]
=n/2[4+27] = 155
n/2 [31] =155
n= 155 * 2
31
therefore n=10
10 terms are there in the AP
[n-1]d=27
9d=27
d=3
so AP is = 2,5,8,11,14,17,20,23,26,29
if it is clear
please mark it as the BRAINLIEST
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