In an AP the first term is 33and the sum to first n terms is 123. Find n and d the common difference?
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Step-by-step explanation:
a0 = 33
sn = n/2(2a +(n-1)d)
123*2=n(66+(n-1)d)
246 =66n +(n-1)*n*d
246 is not divisible by 66
hence n# 1
let n=2
we get d= 114/2 =57
let n=3
246-198=2*3*d
48/6 =8= d
let n=4
246-264=3*4*d
-18/12 = -1.5=d
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