in an AP the first term is -5 and last term is 45.if the sum of all the terms is 120,then find n
Answers
Answered by
1
Answer:
sum=n/2(a+l)
120=n/2(-5+45)
240=n(40)
n=240/40
n=6
Answered by
0
Answer:
n=6
Step-by-step explanation:
a= -5
l= 45
sum of all term =120
n=?
sum of all term= n/2[a+l]
120=n/2[-5+45]
120=n/2(40)
120/40=n/2
3×2=n
n=6
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