in an ap the first term is 8 nth terms is 33 and sum of first n term is 123 then find the value of n
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a=8
nth terms is 33
a+(n-1)d=33
(n-1)d=33-a
(n-1)d=25
Sn=123
n/2(2a+(n-1)d)=123
n/2(2*8+25)=123
n/2(16+25)=123
n=123*2/41
n=6
nth terms is 33
a+(n-1)d=33
(n-1)d=33-a
(n-1)d=25
Sn=123
n/2(2a+(n-1)d)=123
n/2(2*8+25)=123
n/2(16+25)=123
n=123*2/41
n=6
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