in an AP the sum of first n terms is 3n²+n . find its 22nd term
answer is 130 but solve it full explaintion Please
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Step-by-step explanation:
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Let S
n
be the sum of n terms of an AP with first term a and common difference d.
Since S
n
=3n
2
−n and d=6
⇒S
n
=
2
n
(2a+(n−1)d)=3n
2
−n
2
n
(2a+(n−1)6)=3n
2
−n
n(a+(n−1)3)=3n
2
−n
(a+3n−3)=3n−1
a=2
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